AP EAMCET · Maths · Pair of Lines
The combined equation of the diagonals of the square formed by the two pairs of straight lines given by \(x y+4 x-3 y-12=0\) and \(x y-3 x+4 y-12=0\) is
- A \(x^2-2 x y+y^2+x-y=0\)
- B \(x^2+2 x y+y^2+x+y=0\)
- C \(x^2-y^2+x+y=0\)
- D \(x^2-y^2+x-y=0\)
Answer & Solution
Correct Answer
(D) \(x^2-y^2+x-y=0\)
Step-by-step Solution
Detailed explanation
Lines from `\(x y+4 x-3 y-12=0\)`: `\((x-3)(y+4)=0 \Rightarrow x=3, y=-4\)` Lines from `\(x y-3 x+4 y-12=0\)`: `\((x+4)(y-3)=0 \Rightarrow x=-4, y=3\)` Vertices of square: `\((3,3), (3,-4), (-4,-4), (-4,3)\)` Diagonal 1 (through `\((3,3)\)` and `\((-4,-4)\)`): `…
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