AP EAMCET · Maths · Circle

$A B C D$ is a square with side $16$ units and $A$ is the origin. If the equation of the circle circumscribing the square $A B C D$ is $x^{2} + y^{2} = 4 k (x + y),$ then $k =$

A $2$
B $4$
C $16$
D $64$

Verified Solution

Answer & Solution

Correct Answer

(B) $4$

Step-by-step Solution

Detailed explanation

Clearly, AC is the diameter. So, equation of circle in diameter form is x-0x-16+y-0y-16=0 ⇒x2-16x+y2-16y=0 ⇒x2+y2=16x+y Comparing with the given equation, we get k=4.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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ABCD is a square with side 16 units and A is the origin. If the equation of the circle circumscribing the square ABCD is x2+y2=4k(x+y), then k=

Step-by-step Solution

$A B C D$ is a square with side $16$ units and $A$ is the origin. If the equation of the circle circumscribing the square $A B C D$ is $x^{2} + y^{2} = 4 k (x + y),$ then $k =$