AP EAMCET · PHYSICS · Semiconductors
In a transistor, when the emitter current changes by 9.85 \(\mathrm{mA}\), the collector current changes to \(9.5 \mathrm{~mA}\). Then the base current is
- A \(0.05 \mathrm{~mA}\)
- B \(0.85 \mathrm{~mA}\)
- C \(0.8 \mathrm{~mA}\)
- D \(0.35 \mathrm{~mA}\)
Answer & Solution
Correct Answer
(D) \(0.35 \mathrm{~mA}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{I}_E=9.85 \mathrm{~mA} \\ & \mathrm{I}_{\mathrm{C}}=9.5 \mathrm{~mA} \\ & \mathrm{I}_E=\mathrm{I}_B+\mathrm{I}_{\mathrm{C}} \end{aligned}\) Base current, \(I_B=I_E-I_C\) \(=9.85-9.5=0.35 \mathrm{~mA}\)
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