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AP EAMCET · PHYSICS · Electrostatics

The sum of two point positive charges separated by a distance of 1.5 m in air is \(25 \mu \mathrm{C}\). If the electrostatic force between the two charges is 0.6 N, then the difference between the two charges is

  1. A \(5 \mu \mathrm{C}\)
  2. B \(8 \mu \mathrm{C}\)
  3. C \(3 \mu \mathrm{C}\)
  4. D \(6 \mu \mathrm{C}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(5 \mu \mathrm{C}\)

Step-by-step Solution

Detailed explanation

\(q_1 q_2 = \frac{F r^2}{k} = \frac{(0.6 \, \mathrm{N})(1.5 \, \mathrm{m})^2}{9 \times 10^9 \, \mathrm{N \cdot m^2/C^2}} = 1.5 \times 10^{-10} \, \mathrm{C^2}\)…