AP EAMCET · PHYSICS · Thermal Properties of Matter
A steel ball of mass \(200 \mathrm{~g}\) falls freely from a height of 20 \(\mathrm{m}\) and bounces to a height of \(10.8 \mathrm{~m}\) from the ground. If the energy lost in this process is absorbed by the ball, the rise in its temperature is ( \(\mathrm{g}=10 \mathrm{~ms}^{-2}\), specific heat capacity of steel is \(460 \mathrm{Jkg}^{-1} \mathrm{~K}^{-1}\) )
- A \(0.1^{\circ} \mathrm{C}\)
- B \(1^{\circ} \mathrm{C}\)
- C \(0.2^{\circ} \mathrm{C}\)
- D \(2^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(D) \(2^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Apply the conservation of energy \(\mathrm{mg}\left(\mathrm{h}_1-\mathrm{h}_2\right)=\mathrm{mc} \Delta \mathrm{T}\)…
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