AP EAMCET · PHYSICS · Magnetic Effects of Current
A charged particle moving along a straight line path enters a uniform magnetic field of 4 mT at right angles to the direction of the magnetic field. If the specific charge of the charged particle is \(8 \times 10^7 \mathrm{C} \mathrm{kg}^{-1}\), the angular velocity of the particle in the magnetic field is
- A \(64 \times 10^4 \mathrm{rad} \mathrm{s}^{-1}\)
- B \(32 \times 10^4 \mathrm{rad} \mathrm{s}^{-1}\)
- C \(16 \times 10^4 \mathrm{rad} \mathrm{s}^{-1}\)
- D \(48 \times 10^4 \mathrm{rad} \mathrm{s}^{-1}\)
Answer & Solution
Correct Answer
(B) \(32 \times 10^4 \mathrm{rad} \mathrm{s}^{-1}\)
Step-by-step Solution
Detailed explanation
\(B=4 \mathrm{mT}=4 \times 10^{-3} \mathrm{~T}, \frac{\mathrm{q}}{\mathrm{m}}=8 \times 10^7 \mathrm{c} \mathrm{kg}^{-1}\) \(\therefore \quad\) Angular velocity, \(\mathrm{w}=\frac{\mathrm{B}_{\mathrm{q}}}{\mathrm{m}}=4 \times 10^{-3} \times 8 \times 10^7\)…
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