AP EAMCET · Maths · Circle
If the lines \(2 x+y+12=0, k x-3 y-10=0\) are conjugate with respect to the circle \(x^2+y^2-4 x+3 y-1=0\), then \(k=\)
- A 4
- B -9
- C -3
- D -5
Answer & Solution
Correct Answer
(A) 4
Step-by-step Solution
Detailed explanation
Lines \(2 x+y+12=0, k x-3 y-10=0\) are conjugate with respect to given circle. \(\therefore\) Pole of line \(2 x+y+12=0\) lie on the line \(k x-3 y-10=0\) Equation of polar of pole \((x, y)\) to circle \(x^2+y^2-4 x+3 y-1=0\) is…
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