AP EAMCET · PHYSICS · Mechanical Properties of Solids
If the ratio of lengths, radii and Young's modulus of steel and brass wires shown in the figure are \(a, b\) and \(c\) respectively, the ratio between the increase in lengths of brass and steel wires would be
- A \(\frac{b^2 a}{2 c}\)
- B \(\frac{b c}{2 a^2}\)
- C \(\frac{b a^2}{2 c}\)
- D \(\frac{a}{2 b^2 c}\)
Answer & Solution
Correct Answer
(A) \(\frac{b^2 a}{2 c}\)
Step-by-step Solution
Detailed explanation
Free body diagram of the two blocks are Given, \(\quad \frac{l_1}{l_2}=a, \frac{r_1}{r_2}=b, \frac{Y_1}{Y_2}=c\) Let Young's modulus of steel is \(Y_1\) and of brass is \(Y_2\). \(\therefore \quad Y_1=\frac{F_1 \cdot l_1}{A_1 \cdot \Delta l_1}\) ...(i) and…
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