AP EAMCET · Maths · Vector Algebra
Let \(\vec{a}=3 \hat{i}+4 \hat{j}-5 \hat{k}, \vec{b}=2 \hat{i}+\hat{j}-2 \hat{k}\). The projection of the sum of the vectors \(\vec{a}, \vec{b}\) on the vector perpendicular to the plane of \(\vec{a}, \vec{b}\) is
- A 0
- B \(4 \sqrt{2}\)
- C \(7 \sqrt{2}\)
- D \(\frac{1}{\sqrt{2}}\)
Answer & Solution
Correct Answer
(A) 0
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Projection }=\frac{(\vec{a} \times \vec{b})}{|\vec{a} \times \vec{b}|} \cdot(\vec{a}+\vec{b}) \\ & =\frac{1}{|\vec{a} \times \vec{b}|}=0 \quad\left(\because\left[\begin{array}{lll}a & b & a\end{array}\right]+\left[\begin{array}{lll}a & b &…
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