AP EAMCET · PHYSICS · Mechanical Properties of Fluids
A glass capillary tube of inner diameter 0.28 \(\mathrm{mm}\) is lowered vertically into water in a vessel. The pressure to be applied on the water in the capillary tube so that water level in the tube is same as that in the vessel (in \(\mathrm{N} / \mathrm{m}^2\) ) is
Surface tension of water \(=0.07 \mathrm{~N} / \mathrm{m}\)
Atmospheric pressure \(=10^5 \mathrm{~N} / \mathrm{m}^2\)
- A \(10^3\)
- B \(99 \times 10^3\)
- C \(100 \times 10^3\)
- D \(101 \times 10^3\)
Answer & Solution
Correct Answer
(D) \(101 \times 10^3\)
Step-by-step Solution
Detailed explanation
Diameter \(d=0.28 \mathrm{~mm}=0.28 \times 10^{-3} \mathrm{~m}\) Radius \(r=\frac{d}{2}=0.14 \times 10^{-3} \mathrm{~m}\) Surface tension \(T=0.07 \mathrm{~N} / \mathrm{m}\) \[ T=\frac{r h d g}{2 \cos \theta} \] For water \(\theta=0^{\circ}\)…
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