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AP EAMCET · PHYSICS · Oscillations

One end of a long metallic wire of length \(L\), area of cross-section \(A\) and Young's modulus \(Y\) is tied to the ceiling. The other end is tied to a massless spring of force constant \(k\) and a mass \(m\) is hung from the free end of the spring. If \(m\) is slightly pulled down and released, then its time period of oscillation is

  1. A \(2 \pi \sqrt{\frac{m}{k}}\)
  2. B \(2 \pi \sqrt{\frac{m Y A}{k L}}\)
  3. C \(2 \pi \sqrt{\frac{m(k A+Y L)}{k Y A}}\)
  4. D \(2 \pi \sqrt{\frac{m(k L+Y A)}{k Y A}}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(2 \pi \sqrt{\frac{m(k L+Y A)}{k Y A}}\)

Step-by-step Solution

Detailed explanation

For oscillating mass at end of a rod. Restoring force \( =\frac{Y A}{L} \cdot x \) So, \(k_1=\) spring constant for a rod is \(\frac{Y A}{L}\). If a rod and spring are connected, then it is a series combination. So, \(\left(k_{\text {eq }}\right)\)…
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