AP EAMCET · PHYSICS · Alternating Current
An \(L-C\) circuit contains \(196 \mathrm{pF}\) capacitor and a \(441 \mu \mathrm{H}\) inductor. The frequency of electromagnetic radiation emitted by antenna coupled to the \(L-C\) circuit is
- A \(7.96 \times 10^5 \mathrm{~Hz}\)
- B \(54.1 \times 10^5 \mathrm{~Hz}\)
- C \(79.6 \times 10^5 \mathrm{~Hz}\)
- D \(5.41 \times 10^5 \mathrm{~Hz}\)
Answer & Solution
Correct Answer
(D) \(5.41 \times 10^5 \mathrm{~Hz}\)
Step-by-step Solution
Detailed explanation
Given, capacitance, \(C=196 \mathrm{pF}=196 \times 10^{-12} \mathrm{~F}\) Inductance, \(L=441 \mu \mathrm{H}\) \[ =441 \times 10^{-6} \mathrm{H} \] Since, frequency, \(f=\frac{1}{2 \pi \sqrt{L C}}\)…
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