AP EAMCET · PHYSICS · Units and Dimensions
If the charge of electron \(e\), mass of electron \(m\), speed of light in vacuum \(c\) and Planck's constant \(h\) are taken as fundamental quantities, then the permeability of vacuum \(\mu_0\) can be expressed as
- A \(\frac{h}{m c^2}\)
- B \(\frac{h c}{m e^2}\)
- C \(\frac{h}{c e^2}\)
- D \(\frac{m c^2}{h e^2}\)
Answer & Solution
Correct Answer
(C) \(\frac{h}{c e^2}\)
Step-by-step Solution
Detailed explanation
We can expressed the permeability of vacuum, \(\mu_0 \propto e^a m^b c^c h^d\) or \(\mu_0=k e^a m^b c^c h^d\) ...(i) Where, \(k\) is a dimensional constant. As we know that, Dimension of…
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