AP EAMCET · Maths · Probability
A die is thrown twice. Let A be the event of getting a prime number when the die is thrown first time and \(B\) be the event of getting an even number when the die is thrown second time. Then \(\mathrm{P}(\mathrm{A} / \overline{\mathrm{B}})=\)
- A \(\frac{1}{2}\)
- B \(\frac{2}{3}\)
- C \(\frac{1}{5}\)
- D \(\frac{3}{5}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(P(A) = \frac{\text{Number of prime numbers}}{\text{Total outcomes}} = \frac{3}{6} = \frac{1}{2}\) \(P(\overline{B}) = \frac{\text{Number of odd numbers}}{\text{Total outcomes}} = \frac{3}{6} = \frac{1}{2}\) Events A and B (and thus A and \(\overline{B}\)) are independent.…
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