AP EAMCET · PHYSICS · Laws of Motion
A balloon with mass ' \(m\) ' is descending vertically with an acceleration ' \(a\) ' (where \(\mathrm{a} < \mathrm{g}\) ). The mass to be removed from the balloon, so that it starts moving vertically up with an acceleration ' \(a\) ' is
- A \(\frac{m a}{g+a}\)
- B \(\frac{m a}{g-a}\)
- C \(\frac{2 m a}{g+a}\)
- D \(\frac{2 m a}{g-a}\)
Answer & Solution
Correct Answer
(C) \(\frac{2 m a}{g+a}\)
Step-by-step Solution
Detailed explanation
Initial state: \(mg - B = ma \Rightarrow B = m(g-a)\) Final state: \(B - (m - m_{removed})g = (m - m_{removed})a\) \(m(g-a) - (m - m_{removed})g = (m - m_{removed})a\) \(mg - ma - mg + m_{removed}g = ma - m_{removed}a\) \(m_{removed}g + m_{removed}a = 2ma\)…
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