AP EAMCET · Maths · Complex Number
If \(\omega\) is the cube root of unity \(\frac{a+b \omega+c \omega^2}{c+a \omega+b \omega^2}+\frac{a+b \omega+c \omega^2}{b+c \omega+a \omega^2}=\)
- A 2
- B -2
- C 1
- D -1
Answer & Solution
Correct Answer
(D) -1
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \frac{a+b \omega+c \omega^2}{c+a \omega+b \omega^2}+\frac{a+b \omega+c \omega^2}{b+c \omega+a \omega^2} \\ & \frac{a+b \omega+c \omega^2}{c+a \omega+b \omega^2}+\frac{\omega^2\left(a+b \omega+c \omega^2\right)}{b \omega^2+c+a \omega} \\ &…
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