AP EAMCET · PHYSICS · Kinetic Theory of Gases
For a molecule of an ideal gas, the number density is \(2 \sqrt{2} \times 10^8 \mathrm{~cm}^{-3}\) and the mean free path is \(\frac{10^{-2}}{\pi} \mathrm{cm}\). The diameter of the gas molecule is
- A \(5 \times 10^{-4} \mathrm{~cm}\)
- B \(0.5 \times 10^{-4} \mathrm{~cm}\)
- C \(2.5 \times 10^{-4} \mathrm{~cm}\)
- D \(4 \times 10^{-4} \mathrm{~cm}\)
Answer & Solution
Correct Answer
(A) \(5 \times 10^{-4} \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
Mean free path,…
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