AP EAMCET · PHYSICS · Communication System
A TV tower has a height \(160 \mathrm{~m}\). Its coverage range is nearly (Earth's radius, \(R_e=6400 \mathrm{~km}\))
- A \(45255 \mathrm{~m}\)
- B \(55265 \mathrm{~m}\)
- C \(452.55 \mathrm{~km}\)
- D \(552.65 \mathrm{~m}\)
Answer & Solution
Correct Answer
(A) \(45255 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Given, height of a TV tower, \(h=160 \mathrm{~m}\) Radius of earth, \(R=6400 \mathrm{~km}=6.4 \times 10^6 \mathrm{~m}\) Coverage range of TV tower is given by \(d=\sqrt{2 R h}=\sqrt{2 \times 6.4 \times 10^6 \times 160}=45254.8=45255 \mathrm{~m}\)
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