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AP EAMCET · PHYSICS · Capacitance

Eight drops of mercury, each of same radius and same charge combine to form a bigger drop. The ratio of capacitance of the bigger drop to that of each smaller drop is

  1. A \(8: 1\)
  2. B \(4: 1\)
  3. C \(2: 1\)
  4. D \(1: 1\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2: 1\)

Step-by-step Solution

Detailed explanation

Number of drops, \(\mathrm{n}=8\) Let, \(\mathrm{r}\) is radius of smaller drop and \(\mathrm{R}\) is the radius of Bigger drop. Volume of smaller drops \& bigger drop remains same \[ 8 \times \frac{4}{3} \pi r^3=\frac{4}{3} \pi r^3 \Rightarrow R=2 r \] Capacitance of spherical…
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