AP EAMCET · PHYSICS · Current Electricity
Current sensitivities of two galvanometers \(\mathrm{G}_1\) and \(\mathrm{G}_2\) of resistances \(100 \Omega\) and \(50 \Omega\) are \(10^8 \mathrm{div} / \mathrm{A}\) and \(0.5 \times 10^5 \mathrm{div} / \mathrm{A}\) respectively. The galvanometer in which the voltage sensitivity is more is
- A Same in both galvanometers
- B More in \(\mathrm{G}_2\)
- C Zero
- D More in \(\mathrm{G}_1\)
Answer & Solution
Correct Answer
(D) More in \(\mathrm{G}_1\)
Step-by-step Solution
Detailed explanation
\(\mathrm{G}_1=100 \Omega, \mathrm{G}_2=50 \Omega\) \(\mathrm{I}_{\mathrm{S} 1}=10^8 \mathrm{div} / \mathrm{A}, \mathrm{I}_{\mathrm{S} 2}=0.5 \times 10^5 \mathrm{div} / \mathrm{A}\) Voltage sensitivity, \(V_S=\frac{I_S}{G}\)…
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