AP EAMCET · PHYSICS · Magnetic Effects of Current
A beam of protons moving with a velocity \(1.6 \times 10^5 \mathrm{~ms}^{-1}\) enter a uniform magnetic field of \(\frac{\pi}{10} \mathrm{~T}\) at an angle \(60^{\circ}\) to the direction of the field. The pitch of the helical path of the protons is (mass of proton \(=1.6 \times 10^{-27} \mathrm{~kg}\))
- A \(1.6 \times 10^{-2} \mathrm{~m}\)
- B \(2.6 \times 10^{-2} \mathrm{~m}\)
- C \(0.16 \times 10^{-2} \mathrm{~m}\)
- D \(0.016 \times 10^{-2} \mathrm{~m}\)
Answer & Solution
Correct Answer
(A) \(1.6 \times 10^{-2} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
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