AP EAMCET · PHYSICS · Dual Nature of Matter
Two light waves of wavelengths \(600 \mathrm{~nm}\) and \(200 \mathrm{~nm}\) incident on a metal surface. The maximum velocity of photoelectrons produced due to one wavelength is \(\frac{1}{3}\) of the maximum velocity of the photoelectrons produced due to the other wavelength, then the work function of the metal is
- A \(\frac{\mathrm{hc}}{8} \times 10^7 \mathrm{~J}\)
- B \(\frac{8}{\mathrm{hc}} \times 10^7 \mathrm{~J}\)
- C \(\frac{\mathrm{hc}}{4} \times 10^7 \mathrm{~J}\)
- D \(\frac{\mathrm{hc}}{9} \times 10^7 \mathrm{~J}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mathrm{hc}}{8} \times 10^7 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
By Einstein photoelectric equation…
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