AP EAMCET · PHYSICS · Units and Dimensions
If the force is given by \(F=a t+b t^2\) with \(t\) as time. The dimensions of \(a\) and \(b\) are
- A \(\left[\mathrm{MLT}^{-4}\right],\left[\mathrm{MLT}^{-2}\right]\)
- B \(\left[\mathrm{MLT}^{-3}\right],\left[\mathrm{MLT}^{-4}\right]\)
- C \(\left[\mathrm{ML}^2 \mathrm{~T}^{-3}\right],\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]\)
- D \(\left[\mathrm{ML}^2 \mathrm{~T}^{-3}\right],\left[\mathrm{ML}^3 \mathrm{~T}^{-4}\right]\)
Answer & Solution
Correct Answer
(B) \(\left[\mathrm{MLT}^{-3}\right],\left[\mathrm{MLT}^{-4}\right]\)
Step-by-step Solution
Detailed explanation
Dimension of \(a t=\) Dimension of \(F\) \([a t]=[F]\) \([a]=\left[\frac{F}{t}\right]\) \([a]=\left[\frac{\mathrm{MLT}^{-2}}{\mathrm{~T}}\right]\) \([a]=\left[\mathrm{MLT}^{-3}\right]\) Dimension of \(b t^2=\) Dimension of \(F\) \(\left[b t^2\right]=[F]\)…
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