AP EAMCET · Maths · Circle
The centre of the circle which passes through the vertices of the triangle formed by the lines \(y=0, y=x\) and \(2 x+3 y=10\), is
- A \(\left(-\frac{5}{2},-\frac{1}{2}\right)\)
- B \(\left(\frac{5}{2},-\frac{1}{2}\right)\)
- C \(\left(-\frac{1}{2},-\frac{1}{2}\right)\)
- D \(\left(\frac{5}{2}, \frac{1}{2}\right)\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{5}{2},-\frac{1}{2}\right)\)
Step-by-step Solution
Detailed explanation
Given equation of sides are \(\begin{aligned} y & =0 \quad \ldots (i) \\ y & =x \quad \ldots (ii) \\ 2 x+3 y & =10 \quad \ldots (iii) \end{aligned}\) Solving Eqs. (i) and (iii) to get vertex ' \(A\) ' \(\therefore \quad A=(5,0)\) Solving (i) and (ii) to get vertex ' \(B\) '…
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