AP EAMCET · PHYSICS · Electrostatics
As shown in the figure, the work done to move the charge ' \(Q\) ' from point \(C\) to point D along the semi-circle CRD is
- A \(\frac{\mathrm{qQ}}{4 \pi \varepsilon_0 \mathrm{~d}}\)
- B \(\frac{\mathrm{qQ}}{2 \pi \varepsilon_0 \mathrm{~d}}\)
- C \(\frac{-q \mathrm{Q}}{6 \pi \varepsilon_0 \mathrm{~d}}\)
- D \(\frac{-\mathrm{qQ}}{4 \pi \varepsilon_0 \mathrm{~d}}\)
Answer & Solution
Correct Answer
(C) \(\frac{-q \mathrm{Q}}{6 \pi \varepsilon_0 \mathrm{~d}}\)
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