AP EAMCET · Maths · Trigonometric Equations
The number of solutions of \(\sin 2 x+\cos 4 x=2\) in the interval \([-\pi, \pi]\) is
- A 3
- B 2
- C 0
- D 1
Answer & Solution
Correct Answer
(C) 0
Step-by-step Solution
Detailed explanation
For \(\sin 2 x+\cos 4 x=2\), we must have \(\sin 2 x=1\) and \(\cos 4 x=1\). \(\sin 2 x=1 \Rightarrow 2x = \frac{\pi}{2} + 2n\pi \Rightarrow x = \frac{\pi}{4} + n\pi\). In \([-\pi, \pi]\), possible values for \(x\) are \(\{ \frac{\pi}{4}, -\frac{3\pi}{4} \}\).…
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