AP EAMCET · Chemistry · Chemical Kinetics
The time taken for half of the initial amount of \(\mathrm{N}_2 \mathrm{O}_5\) to decompose is \(12 \mathrm{~min}\) at \(310 \mathrm{~K}\) and \(2 \mathrm{hrs}\) at \(300 \mathrm{~K}\). The activation energy of reaction in \(\mathrm{kJ}\) is \(\left(\mathrm{R}=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)\)
- A \(177.76\)
- B \(17.776\)
- C \(355.52\)
- D \(35.552\)
Answer & Solution
Correct Answer
(A) \(177.76\)
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Detailed explanation
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