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AP EAMCET · Maths · Properties of Triangles

In a triangle ABC, if 3sinA+4cosB=6 and 4sinB+3cosA=1, then sin(A+B) is equal to

  1. A 1
  2. B 12
  3. C 0
  4. D cosC
Verified Solution

Answer & Solution

Correct Answer

(B) 12

Step-by-step Solution

Detailed explanation

Given, 3sinA+4cosB=6 and 4sinB+3cosA=1 On squaring and adding both the equations we get, 3sinA+4cosB2+4sinB+3cosA2=62+12 ⇒9sin2A+16cos2B+24sinAcosB+16sin2B+9cos2A+24sinBcosA=37 ⇒9sin2A+cos2A+16cos2B+sin2B+24sinAcosB+sinBcosA=37 Using sin2A+cos2A=1 and…