AP EAMCET · PHYSICS · Mechanical Properties of Solids
A uniform wire of length \(10 \mathrm{~m}\) and diameter \(0.6 \mathrm{~mm}\) is stretched by \(6 \mathrm{~mm}\) with certain force. If the Poisson's ratio of the material of the wire is 0.3 , then the change in diameter of the wire is
- A \(108 \times 10^{-8} \mathrm{~m}\)
- B \(108 \times 10^{-6} \mathrm{~m}\)
- C \(10.8 \times 10^{-8} \mathrm{~m}\)
- D \(1.08 \times 10^{-8} \mathrm{~m}\)
Answer & Solution
Correct Answer
(C) \(10.8 \times 10^{-8} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Given, length of the wire, \(L=10 \mathrm{~m}\), diameter, \(D=0.6 \times 10^{-3} \mathrm{~m}\), poisson's ratio, \(\sigma=0.3\) and change in wire length, \(\Delta L=6 \times 10^{-3} \mathrm{~m}\) As poisson's ratio,…
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