AP EAMCET · Maths · Probability
A random variable \(X\) has the probability distribution as given below. Let \(E=[X \mid X\) is prime number] and \(F=\{X \mid X < 4\}\), then \(P(E \cup F)=\)
\(\begin{array}{|c|c|c|c|c|c|c|c|c|}
\hline X & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\
\hline P(X) & K & 2 K & K^2 & 2 K^2 & 5 K^2 & K & K & 2 K \\
\hline
\end{array}\)
- A \(\frac{38}{64}\)
- B \(\frac{39}{64}\)
- C \(\frac{42}{64}\)
- D \(\frac{17}{64}\)
Answer & Solution
Correct Answer
(A) \(\frac{38}{64}\)
Step-by-step Solution
Detailed explanation
Given probability distribution is \(\begin{array}{c|c|c|c|c|c|c|c|c} \hline \boldsymbol{X} & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ \hline P(X) & K & 2 K & K^2 & 2 K^2 & 5 K^2 & K & K & 2 K \\ \hline \end{array}\)…
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