AP EAMCET · Maths · Probability
Two persons \(A\) and \(B\) take part in a shooting competition. \(A\) can hit the target with a probability of 0.6 . \(B\) can hit the target with a probability of 0.8 . \(A\) has the first shoot, past which they strike alternatively. Then, the probability that \(A\) wins the competition is
- A \(\frac{7}{10}\)
- B \(\frac{15}{23}\)
- C \(\frac{2}{3}\)
- D \(\frac{11}{17}\)
Answer & Solution
Correct Answer
(B) \(\frac{15}{23}\)
Step-by-step Solution
Detailed explanation
Given that, \(P(A)=0.6\) and \(P(B)=0.8\) \(\Rightarrow P\left(A^{\prime}\right)=0.4\) and \(\left(P\left(B^{\prime}\right)=0.2\right.\) \(\therefore\) Probability that \(A\) wins \(=P(A)+P\left(A^{\prime}\right) P\left(B^{\prime}\right) P(A)\)…
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