AP EAMCET · PHYSICS · Atomic Physics
The ratio of radii of \(3^{\text {rd }}\) and \(6^{\text {th }}\) Bohr's orbit in a hydrogen atom is
- A \(0.25\)
- B \(0.33\)
- C \(4\)
- D \(3\)
Answer & Solution
Correct Answer
(A) \(0.25\)
Step-by-step Solution
Detailed explanation
We have, \(\frac{\mathrm{r}_3}{\mathrm{r}_6}=\frac{3^2}{6^2}=\frac{9}{36}=0.25 \quad\left[\because \mathrm{r}_{\mathrm{n}} \propto \mathrm{n}^2\right]\)
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