AP EAMCET · PHYSICS · Laws of Motion
A car of mass \(1500 \mathrm{~kg}\) is moving with \(20 \mathrm{~ms}^{-1}\) velocity. If the breaks are applied it comes to rest in 5 seconds, then the retarding force is
- A \(9000 \mathrm{~N}\)
- B \(6000 \mathrm{~N}\)
- C \(12000 \mathrm{~N}\)
- D \(3000 \mathrm{~N}\)
Answer & Solution
Correct Answer
(B) \(6000 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Retarding force \(\mathrm{F}_{\text {retard }}=\frac{\mathrm{m} \Delta \mathrm{v}}{\Delta \mathrm{t}}=\frac{1500 \times(0-20)}{5}\) \[ =\frac{1500 \times-20}{5}=-6000 \mathrm{~N} \]
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