AP EAMCET · PHYSICS · Laws of Motion
A car is moving along a circular path having coefficient of friction 0.5 and radius of curvature \(16.2 \mathrm{~m}\). Then the maximum velocity of the car that can travel without falling outwards is
(Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(18 \mathrm{~ms}^{-1}\)
- B \(32.4 \mathrm{kmh}^{-1}\)
- C \(18 \mathrm{kmh}^{-1}\)
- D \(32.4 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(B) \(32.4 \mathrm{kmh}^{-1}\)
Step-by-step Solution
Detailed explanation
Coefficient of friction, \(\mu=0.5\) Radius of curvature, \(r=16.2 \mathrm{~m}\) Along the radial direction, we have friction provides the centripetal force, \(\mathrm{f}=\mu \mathrm{N}=\mu \mathrm{mg}\)…
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