AP EAMCET · PHYSICS · Motion In One Dimension
A particle moving along a straight line covers the first half of the distance with a speed of \(3 \mathrm{~m} \mathrm{~s}^{-1}\), the other half of the distance is covered in two equal time intervals with speeds of \(4.5 \mathrm{~m} \mathrm{~s}^{-1}\) and \(7.5 \mathrm{~m} \mathrm{~s}^{-1}\) respectively, then the average speed of particle during the motion is
- A \(4.0 \mathrm{~m} \mathrm{~s}^{-1}\)
- B \(5.0 \mathrm{~m} \mathrm{~s}^{-1}\)
- C \(5.5 \mathrm{~m} \mathrm{~s}^{-1}\)
- D \(4.8 \mathrm{~m} \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(A) \(4.0 \mathrm{~m} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
\(v_{avg,second\_half} = \frac{4.5 + 7.5}{2}\) \(v_{avg,second\_half} = \frac{12}{2} = 6 \mathrm{~m} \mathrm{~s}^{-1}\) \(v_{avg,total} = \frac{2}{\frac{1}{v_1} + \frac{1}{v_{avg,second\_half}}}\) \(v_{avg,total} = \frac{2}{\frac{1}{3} + \frac{1}{6}}\)…
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