AP EAMCET · PHYSICS · Waves and Sound
A source of sound \(S\) in the form of a block kept on a smooth horizontal surface is connected to a spring, as shown in the figure. If the spring oscillates with an amplitude of \(50 \mathrm{~cm}\) along horizontal between the wall and the observer \(O\), the maximum frequency heard by the observer is \(12.5 \%\) more than the minimum frequency heard by him. If the mass of the source of sound is \(100 \mathrm{~g}\), the force constant of the spring is (Speed of sound in air is \(340 \mathrm{~ms}^{-1}\) )
- A \(40 \mathrm{Nm}^{-}\)
- B \(80 \mathrm{Nm}^{-1}\)
- C \(160 \mathrm{Nm}^{-1}\)
- D \(320 \mathrm{Nm}^{-1}\)
Answer & Solution
Correct Answer
(C) \(160 \mathrm{Nm}^{-1}\)
Step-by-step Solution
Detailed explanation
Given, amplitude of spring, \(A=50 \times 10^{-2} \mathrm{~m}\), maximum frequency heard by observer, \(n_{\text {max }}=1.125 n_{\text {min }}\) mass of sound source, \(m=100 \mathrm{~g}=0.10 \mathrm{~kg}\) and speed of sound, \(v=340 \mathrm{~ms}^{-1}\). As, the apparent…
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