AP EAMCET · Maths · Differential Equations
The general solution of the differential equation \(\left(1+\sin ^2 x\right) \frac{d y}{d x}+y \sin 2 x\) \(=\cos x+\sin ^2 x \cos x\) is
- A \((\sin 2 x) y=\sin ^2 x+c\)
- B \(\left(1+\sin ^2 x\right) y=\sin x-\frac{\sin ^3 x}{3}+c\)
- C \(\left(1+\sin ^2 x\right) y=\sin x+\frac{\sin ^3 x}{3}+c\)
- D \((\sin 2 x) y=\sin x+\sin ^2 x+c\)
Answer & Solution
Correct Answer
(C) \(\left(1+\sin ^2 x\right) y=\sin x+\frac{\sin ^3 x}{3}+c\)
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x} + \frac{\sin 2 x}{1+\sin ^2 x} y = \frac{\cos x(1+\sin ^2 x)}{1+\sin ^2 x}\) \(\frac{d y}{d x} + \frac{2 \sin x \cos x}{1+\sin ^2 x} y = \cos x\) \(IF = e^{\int \frac{2 \sin x \cos x}{1+\sin ^2 x} dx} = e^{\ln(1+\sin ^2 x)} = 1+\sin ^2 x\)…
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