AP EAMCET · PHYSICS · Thermal Properties of Matter
A steel tape of \(300 \mathrm{~cm}\) length is graduated at \(27^{\circ} \mathrm{C}\). The length of a steel rod measured using the tape is found to be \(110 \mathrm{~cm}\) at \(50^{\circ} \mathrm{C}\). The actual length of steel rod at 50 \({ }^{\circ} \mathrm{C}\) is
\(\left(\alpha_{\text {steel }}=1.2 \times 10^{-5} \mathrm{~K}^{-1}\right)\)
- A \(110.03 \mathrm{~cm}\)
- B \(110.10 \mathrm{~cm}\)
- C \(110.07 \mathrm{~cm}\)
- D \(110.62 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(A) \(110.03 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
Let \(L^{\prime}\) be the length of steel rod. \(\begin{aligned} & \mathrm{L}^{\prime}=\mathrm{L}+\mathrm{L} \alpha \Delta \mathrm{T} \\ & =300+300 \times 1.2 \times 10^{-5} \times(50-27) \\ & =300+0.0828=300.0828 \mathrm{~m}\end{aligned}\) The actual length of steel rod at…
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