AP EAMCET · PHYSICS · Oscillations
An object is executing simple harmonic motion with an angular frequency \(\omega\) If the maximum velocity is \(v_{\max }\) then the maximum acceleration of the object is
- A \(\omega^2 v_{\max }\)
- B \(\omega v_{\max }\)
- C \(\omega \sqrt{v_{\max }}\)
- D \(3 \omega v_{\max }\)
Answer & Solution
Correct Answer
(B) \(\omega v_{\max }\)
Step-by-step Solution
Detailed explanation
In SHM maximum velocity of object, \[ \begin{aligned} v_{\max } & =A \omega \\ \Rightarrow \quad A & =\frac{v_{\max }}{\omega} ...(i)\end{aligned} \] Where, \(A\) is amplitude and \(\omega\) is angular velocity. \(\therefore\) Maximum acceleration of the object performing SHM,…
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