AP EAMCET · PHYSICS · Electrostatics
Three point charges shown in the figure lie along a straight line. The energy required to exchange the position of central charge with one of the negative charges is
- A \(\frac{\mathrm{q}^2}{8 \pi \varepsilon_0 \mathrm{a}}\)
- B \(\frac{3 q^2}{8 \pi \varepsilon_0 a}\)
- C \(\frac{\mathrm{q}^2}{4 \pi \varepsilon_0 \mathrm{a}}\)
- D \(\frac{5 \mathrm{q}^2}{4 \pi \varepsilon_0 \mathrm{a}}\)
Answer & Solution
Correct Answer
(C) \(\frac{\mathrm{q}^2}{4 \pi \varepsilon_0 \mathrm{a}}\)
Step-by-step Solution
Detailed explanation
\(U_i = \frac{1}{4 \pi \varepsilon_0} \left( \frac{(q)(-2q)}{a} + \frac{(q)(-q)}{2a} + \frac{(-2q)(-q)}{a} \right) = \frac{1}{4 \pi \varepsilon_0} \left( - \frac{2q^2}{a} - \frac{q^2}{2a} + \frac{2q^2}{a} \right) = - \frac{q^2}{8 \pi \varepsilon_0 a}\)…
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