AP EAMCET · PHYSICS · Electrostatics
A simple pendulum with a bob of mass \(40 \mathrm{~g}\) and charge \(+2 \mu \mathrm{C}\) makes 20 oscillation in \(44 \mathrm{~s}\). A vertical electric field magnitude \(4.2 \times 10^4 \mathrm{NC}^{-1}\) pointing downward is applied. The time taken by the pendulum to make 15 oscillation in the electric field is (acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A 30 s
- B 60 s
- C 90 s
- D 15 s
Answer & Solution
Correct Answer
(A) 30 s
Step-by-step Solution
Detailed explanation
Mass, \(m=40 \mathrm{~g}=0.04 \mathrm{~kg}, q=2 \times 10^{-6} \mathrm{C}\) Now, \(\quad m a=q E\)…
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