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AP EAMCET · PHYSICS · Electrostatics

A simple pendulum with a bob of mass \(40 \mathrm{~g}\) and charge \(+2 \mu \mathrm{C}\) makes 20 oscillation in \(44 \mathrm{~s}\). A vertical electric field magnitude \(4.2 \times 10^4 \mathrm{NC}^{-1}\) pointing downward is applied. The time taken by the pendulum to make 15 oscillation in the electric field is (acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )

  1. A 30 s
  2. B 60 s
  3. C 90 s
  4. D 15 s
Verified Solution

Answer & Solution

Correct Answer

(A) 30 s

Step-by-step Solution

Detailed explanation

Mass, \(m=40 \mathrm{~g}=0.04 \mathrm{~kg}, q=2 \times 10^{-6} \mathrm{C}\) Now, \(\quad m a=q E\)…