AP EAMCET · Maths · Straight Lines
If \(2 x^2-5 x y+2 y^2=0\) represents two sides of a triangle whose centroid is \((1,1)\), then the equation of the third side is
- A \(x+y+3=0\)
- B \(x-y-3=0\)
- C \(x+y-3=0\)
- D \(x-y+3=0\)
Answer & Solution
Correct Answer
(C) \(x+y-3=0\)
Step-by-step Solution
Detailed explanation
Given equation are \(2 x^2-5 x y+2 y^2=0\) \(\Rightarrow(x-2 y)(2 x-y)=0 \Rightarrow x=2 y \& y=2 x\) Let \(A(a, 2 a) \& B(2 b, b)\) and one point \((0,0)\) so \(\frac{a+2 b+0}{3}=1 \Rightarrow a+2 b=3\) ... (i) \(\& \frac{2 a+b+0}{3}=1 \Rightarrow 2 a+b=3\) ... (ii) on solving…
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