AP EAMCET · PHYSICS · Rotational Motion
Radius of gyration of a thin uniform rod of length ' \(L\) ' about an axis passing through its centre and perpendicular to its length is
- A \(\frac{\mathrm{L}}{\sqrt{12}}\)
- B \(\frac{\mathrm{L}}{12}\)
- C \(\mathrm{L} \sqrt{12}\)
- D 12 L
Answer & Solution
Correct Answer
(A) \(\frac{\mathrm{L}}{\sqrt{12}}\)
Step-by-step Solution
Detailed explanation
\( I = \frac{1}{12}ML^2 \) \( Mk^2 = \frac{1}{12}ML^2 \) \( k = \sqrt{\frac{L^2}{12}} = \frac{L}{\sqrt{12}} \)
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