AP EAMCET · PHYSICS · Current Electricity
A resistor of resistance \(R\) is connected between the terminals of a cell of \(\operatorname{emf} E\) and internal resistance \(r\). If \(I\) is the current through the circuit. The terminal potential difference of the cell is given by
- A \(I R\)
- B \(E-I r\)
- C \(\frac{E R}{R+r}\)
- D \(\frac{E-R}{r}\)
Answer & Solution
Correct Answer
(B) \(E-I r\)
Step-by-step Solution
Detailed explanation
Cell of emf \(E\) and internal resistance \(r\) is connected with resistor of resistance \(R\) as shown in the figure. When cell is discharging, then terminal potential difference across the cell is given as \(V=E-I r\) where, \(I\) = current drawn by cells.
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