AP EAMCET · PHYSICS · Work Power Energy
The minimum horizontal speed with which a body must be projected, so that it goes around a smooth vertical circular track of radius \(4 \mathrm{~m}\) is \(\left(g=9.8 \mathrm{~ms}^{-2}\right)\)
- A \(7 \mathrm{~ms}^{-1}\)
- B \(14 \mathrm{~ms}^{-1}\)
- C \(0.7 \mathrm{~ms}^{-1}\)
- D \(1.4 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(B) \(14 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
Radius of circular vertical track, \(r=4 \mathrm{~m}, g=9.8 \mathrm{~ms}^{-2}\) \(\therefore\) Minimum horizontal speed at lowest point to complete the revolution in vertical circle, \(v=\sqrt{5 g r}=\sqrt{5 \times 9.8 \times 4}=\sqrt{196}=14 \mathrm{~ms}^{-1}\)
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