AP EAMCET · PHYSICS · Current Electricity
Number of electrons flowing per second in a conductor carrying a current of \(9 \mathrm{~A}\) is
- A \(3 \times 10^{19}\)
- B \(5.6 \times 10^{19}\)
- C \(5.6 \times 10^{20}\)
- D \(3 \times 10^{20}\)
Answer & Solution
Correct Answer
(B) \(5.6 \times 10^{19}\)
Step-by-step Solution
Detailed explanation
Given that, electric current, \(I=9 \mathrm{~A}\) Let \(n\) be the number of electron passing through a conductor in time \(t\). We know that, \(I=\frac{q}{t}\) and \[ q=n e \]…
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