AP EAMCET · Maths · Circle
The locus of centre of a circle which passes through the origin and cuts off a length of 4 unit from the line \(x=3\) is
- A \(y^2+6 x=0\)
- B \(y^2+6 x=13\)
- C \(y^2+6 x=10\)
- D \(x^2+6 y=13\)
Answer & Solution
Correct Answer
(B) \(y^2+6 x=13\)
Step-by-step Solution
Detailed explanation
Let centre of circle be \(C(-g,-f)\), then equation of circle passing through origin be \(x^2+y^2+2 g x+2 f y=0\)…
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