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AP EAMCET · PHYSICS · Motion In Two Dimensions

A point object moves along an arc of a circle of radius \(R\). Its velocity depends upon the distance covered \(s\) as \(v=K \sqrt{s}\), where \(K\) is a constant. If \(\theta\) is the angle between the total acceleration and tangential acceleration, then

  1. A \(\tan \theta=\sqrt{\frac{S}{R}}\)
  2. B \(\tan \theta=\sqrt{\frac{S}{2R}}\)
  3. C \(\tan \theta={\frac{S}{2R}}\)
  4. D \(\tan \theta={\frac{2S}{R}}\)
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Answer & Solution

Correct Answer

(D) \(\tan \theta={\frac{2S}{R}}\)

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Detailed explanation

\begin{aligned} & \text { } \because \quad \tan \theta=\frac{a_{\text {radial }}}{a_{\text {tangential }}} \\ & =\frac{\frac{V^2}{R}}{a_{\text {tangential }}} \\ & \text { Givn } V=K \sqrt{s} \\ & \Rightarrow \tan \theta=\frac{1}{a_{\text {tangential }}}\left[\frac{1}{R} \times…