AP EAMCET · Maths · Permutation Combination
The number of ways of distributing 500 dissimilar boxes equally among ' 50 ' persons is
- A \(500 ! /(10 !)^{50} \cdot 50\) !
- B \(500 ! /(50 !)^{10} .10\) !
- C \(500 ! /(50 !)^{10}\)
- D \(500 ! /(10 !)^{50}\)
Answer & Solution
Correct Answer
(D) \(500 ! /(10 !)^{50}\)
Step-by-step Solution
Detailed explanation
We know that number of ways in which \(\mathrm{m} \times \mathrm{n}\) distinct things can be distributed among \(\mathrm{n}\) persons. \[ =\frac{(\mathrm{mn}) !}{(\mathrm{m} !)^{\mathrm{n}}} \] \(\therefore\) Number of ways of distributing 500 i.e. \(50 \times 10\) dissimilar…
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