AP EAMCET · Maths · Three Dimensional Geometry
The circum radius of the triangle formed by the points \((2,-1,1),(1,-3,-5)\) and \((3,-4,-4)\) is
- A \(\frac{\sqrt{35}}{2}\)
- B \(\frac{\sqrt{25}}{3}\)
- C \(\sqrt{41}\)
- D \(\frac{\sqrt{41}}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{\sqrt{41}}{2}\)
Step-by-step Solution
Detailed explanation
\( AB^2 = (1-2)^2+(-3-(-1))^2+(-5-1)^2 = 1+4+36 = 41 \) \( BC^2 = (3-1)^2+(-4-(-3))^2+(-4-(-5))^2 = 4+1+1 = 6 \) \( AC^2 = (3-2)^2+(-4-(-1))^2+(-4-1)^2 = 1+9+25 = 35 \)…
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